The first property is that the rank is not changed by the transpose. The proof can be found here.
|rank[||1||3||2||0||1||0||] = 4|
in an earlier example, we have
|rank[||1||-1||0||1||] = 4, nullity[||1||-1||0||1||] = 4 - 4 = 0.|
Note that since the nullity of the 6 by 4 matrix is zero, the null space consists of only the zero vector. This means that the four column vectors (of R6) are linearly independent.
Since the rank means the "essential size", it is always no bigger than the "apparent size".
For an m by n matrix A, rankA ≤ m and n. Moreover,
The proof can be found here. As a consequence of the property, we may characterize the invertibility of a square matrix by the rank and nullity (see this version of the basic principal of linear algebra).
For an n by n matrix A, the following are equivalent.